Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
Q is empty.
↳ QTRS
↳ Overlay + Local Confluence
Q restricted rewrite system:
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
Q is empty.
The TRS is overlay and locally confluent. By [15] we can switch to innermost.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
The set Q consists of the following terms:
f(f(a, a), x0)
Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:
F(f(a, a), x) → F(x, f(a, f(a, f(a, a))))
F(f(a, a), x) → F(a, f(a, f(a, a)))
F(f(a, a), x) → F(a, f(a, a))
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
The set Q consists of the following terms:
f(f(a, a), x0)
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
Q DP problem:
The TRS P consists of the following rules:
F(f(a, a), x) → F(x, f(a, f(a, f(a, a))))
F(f(a, a), x) → F(a, f(a, f(a, a)))
F(f(a, a), x) → F(a, f(a, a))
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
The set Q consists of the following terms:
f(f(a, a), x0)
We have to consider all minimal (P,Q,R)-chains.
We deleted some edges using various graph approximations
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
F(f(a, a), x) → F(x, f(a, f(a, f(a, a))))
F(f(a, a), x) → F(a, f(a, f(a, a)))
F(f(a, a), x) → F(a, f(a, a))
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
The set Q consists of the following terms:
f(f(a, a), x0)
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [13,14,18] contains 1 SCC with 2 less nodes.
↳ QTRS
↳ Overlay + Local Confluence
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ EdgeDeletionProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
F(f(a, a), x) → F(x, f(a, f(a, f(a, a))))
The TRS R consists of the following rules:
f(f(a, a), x) → f(x, f(a, f(a, f(a, a))))
The set Q consists of the following terms:
f(f(a, a), x0)
We have to consider all minimal (P,Q,R)-chains.